510=2w^2-4w

Solution for 510=2w^2-4w equation:

510=2w^2-4w

We move all terms to the left:

510-(2w^2-4w)=0

We get rid of parentheses

-2w^2+4w+510=0

a = -2; b = 4; c = +510;
Δ = b2-4ac
Δ = 42-4·(-2)·510
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-64}{2*-2}=\frac{-68}{-4}
=+17
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+64}{2*-2}=\frac{60}{-4}
=-15
$